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(9x^2)+64x-64=0
a = 9; b = 64; c = -64;
Δ = b2-4ac
Δ = 642-4·9·(-64)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-80}{2*9}=\frac{-144}{18} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+80}{2*9}=\frac{16}{18} =8/9 $
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